How many grams of $ \mathrm{Al_2(SO_4)_3} $ are required to produce 10 L of a 0.5 M solution?
(Molar mass = 342 g/mol)
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Use the formula:
\[
\text{Mass} = Molarity \times Volume \times Molar\, mass
\]
Ensure all units are compatible: Volume in Liters and molar mass in g/mol.