Question

For the reaction: \[ 2A + B \rightarrow 3C \] The rate law is given as: \[ \text{Rate} = k[A]^2[B] \] If the concentration of A is doubled and the concentration of B is halved, how does the rate of the reaction change?

• A. It remains the same.
• B. It increases by a factor of 4.
• C. It doubles.
• D. It decreases by a factor of 2.

Hint:

In chemical kinetics, the rate law describes how the rate of a reaction depends on the concentrations of reactants. Pay attention to the powers of the concentration terms in the rate law when altering reactant concentrations.