Question:medium

For any natural numbers \(m\)\(n\), and \(k\), such that \(k\) divides both \(m + 2n\) and \(3m + 4n\)\(k\) must be a common divisor of

Updated On: Nov 25, 2025
  • m and n
  • 2m and 3n
  • 2m and n
  • m and 2n