For a reaction, the rate law is given by \( \text{rate} = k[A]^2[B] \). If the concentration of \( A \) is doubled and the concentration of \( B \) is halved, how will the rate of the reaction change?
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The rate of a reaction depends on the concentrations of the reactants raised to the powers specified by the rate law. Always use the correct exponents and factor in how concentration changes affect the rate.