Question:medium

Find \(\sqrt{4^{6x^{2}} 25^{y/2} 9 z^{4}}\).

Show Hint

\(\sqrt{a^{m}}=a^{m/2}\). For bases like \(25\) and \(9\), rewrite as powers of primes (\(5^2, 3^2\)) before halving the exponent.
Updated On: Nov 25, 2025
  • \(4^{3x^{2}} 5^{y} 3^{z^{4}}\)
  • \(4^{3x^{2}} 5^{y/2} 9z^{2}\)
  • \(4^{6x} 25^{y/4} 9z^{2}\)
  • \(4^{3x^{2}} 5^{y/2} 3z^{2}\)