Question:medium
Consider the following compounds: K$_2$O$_2$, H$_2$O$_2$, and H$_2$SO$_4$
The oxidation states of the underlined elements in them are, respectively:
Consider the following compounds: K$_2$O$_2$, H$_2$O$_2$, and H$_2$SO$_4$
The oxidation states of the underlined elements in them are, respectively:
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In peroxides, the oxidation state of oxygen is -1. In sulfuric acid, sulfur has an oxidation state of +6, and hydrogen generally has an oxidation state of +1.
Updated On: Nov 26, 2025
- +2, -2, and +6
- +1, -2, and +4
- +4, -4, and +6
- +1, -1, and +6