An ideal gas expands from 2 L to 6 L at a constant temperature of 300 K. Calculate the work done by the gas if pressure remains constant at 2 atm. (1 atm = $1.013 \times 10^5$ Pa)
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For constant pressure expansion, use $W = P \Delta V$; always convert atm to Pa and L to m\textsuperscript{3} before calculation.