Question:medium

A uniformly charged ring of radius \( R \) carries total charge \( Q \). Find the electric field at a point on the axis at a distance \( x = \frac{R}{\sqrt{2}} \) from the center.

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\textbf{Tip:} For field on the axis of a ring, only the axial components add; radial components cancel due to symmetry.
Updated On: Nov 26, 2025
  • \( \frac{1}{4\pi\varepsilon_0} \cdot \frac{Qx}{(R^2 + x^2)^{3/2}} \)
  • \( \frac{1}{4\pi\varepsilon_0} \cdot \frac{QR}{(R^2 + x^2)^{3/2}} \)
  • \( \frac{1}{4\pi\varepsilon_0} \cdot \frac{Q}{R^2} \)
  • \( \frac{1}{4\pi\varepsilon_0} \cdot \frac{Q}{(2R^2)^{3/2}} \)