Question

A triangle is drawn with its vertices on the circle C such that one of its sides is a diameter of C and the other two sides have their lengths in the ratio a:b. If the radius of the circle is r, then the area of the triangle is

• A. \(\frac{2abr^2}{a^2+b^2}\)
• B. \(\frac{abr^2}{a^2+b^2}\)
• C. \(\frac{abr^2}{2(a^2+b^2)}\)
• D. \(\frac{4abr^2}{a^2+b^2}\)