Question

A simple pendulum performing small oscillations at a height R above Earth's surface has a time period of \(T_1 = 4\) s. What would be its time period at a point which is at a height \(2R\) from Earth's surface?

• A. \(T_1 = T_2\)
• B. \(2T_1 = 3T_2\)
• C. \(3T_1 = 2T_2\)
• D. \(2T_1 = T_2\)

Hint:

The time period of a simple pendulum is independent of the height above Earth's surface for small oscillations.