Question

A series LCR circuit is subjected to an AC signal of \( 200 \, \text{V}, 50 \, \text{Hz} \). If the voltage across the inductor (\( L = 10 \, \text{mH} \)) is \( 31.4 \, \text{V} \), then the current in this circuit is:

• A. \( 68 \, \text{A} \)
• B. \( 63 \, \text{A} \)
• C. \( 10 \, \text{A} \)
• D. \( 10 \, \text{mA} \)

Hint:

In an LCR circuit, the current through the inductor can be calculated by dividing the voltage across the inductor by its inductive reactance, \( I = \frac{V_L}{X_L} \), where \( X_L = \omega L \).