Question

A proton, an electron, and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as:

• A. \( \lambda_e>\lambda_\alpha>\lambda_p \)
• B. \( \lambda_\alpha<\lambda_p<\lambda_e \)
• C. \( \lambda_p<\lambda_e<\lambda_\alpha \)
• D. \( \lambda_p>\lambda_e>\lambda_\alpha \)

Hint:

For particles with the same energy, the de-Broglie wavelength is inversely proportional to the square root of their mass.