Question:medium

A projectile is launched with an initial velocity of \( 20 \, \text{m/s} \) at an angle of \( 30^\circ \) with the horizontal. What is the maximum height reached by the projectile? (Take \( g = 10 \, \text{m/s}^2 \))

Show Hint

Maximum height in projectile motion is \( H = \frac{u_y^2}{2g} \), where \( u_y \) is vertical velocity.

Updated On: Nov 26, 2025
  • \( 5 \, \text{m} \)
  • \( 10 \, \text{m} \)
  • \( 15 \, \text{m} \)
  • \( 20 \, \text{m} \)