Question

A particle performs simple harmonic motion with amplitude \( A \). Its speed is tripled at the instant that it is at a distance \( \frac{2A}{3} \) from the equilibrium position. The new amplitude of the motion is:

• A. \( A\sqrt{3} \)
• B. \( \frac{7A}{3} \)
• C. \( \frac{A}{3}\sqrt{41} \)
• D. \( 3A \)

Hint:

In SHM, when velocity changes, use energy conservation or velocity equations to relate the change in speed to the amplitude. Here, tripling the speed leads to a proportional change in amplitude.