Question:medium
A particle of mass \(m\) is moving around the origin with a constant speed \(v\) along a circular path of radius \(R\). When the particle is at \( (0, R) \), its velocity is \( \mathbf{v} = -v \hat{\mathbf{i}} \). The angular momentum of the particle with respect to the origin is :
A particle of mass \(m\) is moving around the origin with a constant speed \(v\) along a circular path of radius \(R\). When the particle is at \( (0, R) \), its velocity is \( \mathbf{v} = -v \hat{\mathbf{i}} \). The angular momentum of the particle with respect to the origin is :
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Angular momentum \( \mathbf{L} = \mathbf{r} \times \mathbf{p} \). Identify the position vector \( \mathbf{r} \) and the linear momentum vector \( \mathbf{p} = m \mathbf{v} \) from the given information. Then compute the cross product using the properties of unit vectors.
Updated On: Nov 26, 2025
- \( mvR \hat{\mathbf{k}} \)
- \( -mvR \hat{\mathbf{k}} \)
- \( mvR \hat{\mathbf{j}} \)
- \( -mvR \hat{\mathbf{j}} \)