Question:medium

A mass of \( 0.5 \, \text{kg} \) is attached to a spring with a spring constant \( k = 200 \, \text{N/m} \). The mass is displaced by \( 0.1 \, \text{m} \) from its equilibrium position. What is the potential energy stored in the spring?

Show Hint

For potential energy stored in a spring, use the formula \( U = \frac{1}{2} k x^2 \), where \( k \) is the spring constant and \( x \) is the displacement from the equilibrium position.
Updated On: Nov 26, 2025
  • \( 1 \, \text{J} \)
  • \( 0.5 \, \text{J} \)
  • \( 2 \, \text{J} \)
  • \( 0.25 \, \text{J} \)