Question

A gas expands from a volume of 2 m³ to 4 m³ against a constant pressure of 5 atm. How much work is done by the gas during expansion? (1 atm = \( 1.01 \times 10^5 \, \text{Pa} \))

• A. \( 2.02 \times 10^5 \, \text{J} \)
• B. \( 1.01 \times 10^5 \, \text{J} \)
• C. \( 5.02 \times 10^5 \, \text{J} \)
• D. \( 1.02 \times 10^5 \, \text{J} \)

Hint:

Remember: The work done during expansion or compression at constant pressure is \( W = P \Delta V \), where \( \Delta V \) is the change in volume.