Question:medium
A box contains 5 red balls and 4 green balls. Two balls are drawn one after another without replacement. What is the probability that the second ball is green, given that the first ball drawn was red?
A box contains 5 red balls and 4 green balls. Two balls are drawn one after another without replacement. What is the probability that the second ball is green, given that the first ball drawn was red?
Show Hint
Use conditional probability formula:
\[
P(B \mid A) = \frac{P(A \cap B)}{P(A)}
\]
and adjust the total count for “without replacement.”
Updated On: Nov 26, 2025
- \(\dfrac{1}{2}\)
- \(\dfrac{5}{18}\)
- \(\dfrac{2}{5}\)
- \(\dfrac{4}{8}\)
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