A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of \( 60^\circ \) by a force of 10 N parallel to the inclined surface. When the block is pushed up by 10 m along the inclined surface, the work done against frictional force is:
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[Given: \( g = 10 \) m/s\( ^2 \), \( \mu_s = 0.1 \)]
A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of \( 60^\circ \) by a force of 10 N parallel to the inclined surface. When the block is pushed up by 10 m along the inclined surface, the work done against frictional force is:
[Given: \( g = 10 \) m/s\( ^2 \), \( \mu_s = 0.1 \)]
Show Hint
- \( 5\sqrt{3} \) J
- \( 5 \) J
- \( 5 \times 10^3 \) J
- \( 10 \) J
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