Question:medium
A ball of mass 0.5 kg is dropped from a height of 10 m. The ball hits the ground and rises to a height of 1.5 m. The impulse imparted to the ball during its collision with the ground is : (Take \(g = 9.8 \, \text{m/s}^2\))
A ball of mass 0.5 kg is dropped from a height of 10 m. The ball hits the ground and rises to a height of 1.5 m. The impulse imparted to the ball during its collision with the ground is : (Take \(g = 9.8 \, \text{m/s}^2\))
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Impulse is the change in momentum: \(J = m(v_f - v_i)\). First, find the velocity just before impact (\(v_i\)) using \(v^2 = u^2 + 2gh\). Then, find the velocity just after impact (\(v_f\)) using the height of rebound and \(v^2 = u^2 + 2as\). Remember to consider the direction of velocities (upwards or downwards) when calculating the change in momentum.
Updated On: Nov 26, 2025
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