Question

A ball is thrown vertically upwards with an initial velocity of 20 m/s. If the acceleration due to gravity is \( 10 \, \text{m/s}^2 \), what is the maximum height reached by the ball?

• A. \( 10 \, \text{m} \)
• B. \( 20 \, \text{m} \)
• C. \( 40 \, \text{m} \)
• D. \( 80 \, \text{m} \)

Hint:

For vertical motion under gravity, the maximum height occurs when the velocity becomes zero. Use \( v^2 = u^2 + 2as \) or \( h = \frac{u^2}{2g} \) to calculate the height, ensuring consistent signs for acceleration.